Java数组实现循环队列

解决队列出队时间复杂度O(n) –> O(1)
int getSize(); // O(1)

boolean isEmpty(); // O(1)

void enqueue(E e); // O(1) 均摊

E dequeue(); // O(1) 均摊

E getFront(); // O(1)

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public class LoopQueue<E> implements Queue<E> {
private E[] data;
private int front, tail;
private int size;

public LoopQueue(int capacity) {
data = (E[]) new Object[capacity + 1];
front = 0;
tail = 0;
size = 0;
}

public LoopQueue() {
this(10);
}

public int getCapacity() {
return data.length - 1;
}

@Override
public boolean isEmpty() {
return front == tail;
}

@Override
public int getSize() {
return size;
}

@Override
public void enqueue(E e) {
if ((tail + 1) % data.length == front) {
resize(getCapacity() * 2);
}
data[tail] = e;
tail = (tail + 1) % data.length;
size++;
}

@Override
public E dequeue() {
if (isEmpty()) {
throw new IllegalArgumentException("队列为空");
}
E ret = data[front];
data[front] = null;
front = (front + 1) % data.length;
size--;
if (size == getCapacity() / 4 && getCapacity() / 2 != 0) {
resize(getCapacity() / 2);
}
return ret;
}

@Override
public E getFront() {
if (isEmpty()) {
throw new IllegalArgumentException("队列为空");
}
return data[front];
}

private void resize(int newCapacity) {
E[] newData = (E[]) new Object[newCapacity + 1];
for (int i = 0; i < size; i++) {
newData[i] = data[(i + front) % data.length];
}
data = newData;
front = 0;
tail = size;
}

@Override
public String toString() {
StringBuilder res = new StringBuilder();
res.append(String.format("Queue: size = %d , capacity = %d\n", size, getCapacity()));
res.append("front [");
for (int i = front; i != tail; i = (i + 1) % data.length) {
res.append(data[i]);
if ((i + 1) % data.length != tail) {
res.append(", ");
}
}
res.append("] tail");
return res.toString();
}
}